x^2+5x+6/(2x+4)=0

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Solution for x^2+5x+6/(2x+4)=0 equation: 



x^2+5x+6/(2x+4)=0



Domain of the equation: (2x+4)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-4

x!=-4/2

x!=-2

x∈R



We multiply all the terms by the denominator


x^2*(2x+4)+5x*(2x+4)+6=0

We multiply parentheses

x^2*(2x+4)+10x^2+20x+6=0

We add all the numbers together, and all the variables

10x^2+x^2*(2x+4)+20x+6=0

We move all terms containing x to the left, all other terms to the right

10x^2+x^2*(2x+4)+20x=-6

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